UGC-NET CS 2017 Nov – II
Q1. If the time is now 4 O’clock, what will be the time after 101 hours from now ?
- 9 O’clock
- 8 O’clock
- 5 O’clock
- 4 O’clock
Ans. 1. 9 O’clock
Explanation: We know that there are 24 hours in a day. So we will take mod for 101 hours i.e. (101 mod 24) = 5. So residue is 5. On adding these remaining 5 hours to the present time will give We know that there are 24 hours in a day, so we will take mod for 101 hours ie (101 mod 24) = 5. So residue is 5. On adding these remaining 5 hours to the present time will give 9 O’CLOCK time.
Q2. Let m=(313)4 and n=(322)4. Find the base 4 expansion of m+n.
- (635)4
- (32312)4
- (21323)4
- (1301)4
Ans. 4. (1301)4
Explanation: We have m=(313)4 and n=(322)4 convert m and n into decimal:
m = 3*42 + 1*41 + 3*40 m = 48 + 4 + 3 m = 55. Now n=3*42 + 2*41 +2*40 n = 48 + 8 +2 n = 58. m + n = 55 + 58 m + n = 113
Now we have to convert 113 in to base 4:
ie step 1-113 % 4 = 1 113 / 4 = 28 step 2- 28 % 4 = 0 28 / 4 = 7 step 3- 7 % 4 = 3 7 / 4 = 1 step 4- 1 % 4 = 1 1 / 4 --> will not divide it in quant. So we have to stop here.
The answer will be Residue from step 4 to step 1 inorder i.e. 1301 Ans-(1301)4